Question

For what value of q, (-4) is a zero of the polynomial

x2 –2x – (7q – 3) ​

Answer 1

Given P(-4) = 0

=>

${( - 4)}^{2} - 2 \times ( - 4) - (7q - 3) = 0$

=>

$16 + 8 - 7q + 3 = 0$

=>

$27 - 7q = 0$

=>

$7q = 27$

=> q = 27/7

Answer 2

Step-by-step explanation:

Refer previous answer ❤️