Question

for what value of x both the polynomial x2 - 3 x + 2 and x2 - 6 X + 5 became 0?

Answer 1

2x - 3x + 2 = 0..... (1)
2x - 6x + 5 = 0...... (2)
From (1) and (2), RHS is equal •°• LHS will be equal
•°• 2x- 3x +2 = 2x - 6x + 5
-3x + 2 = -6x + 5
-3x + 6x = 5 - 2
3x = 3
X= 1
...........
Hope this helps ^_^