Question

for what values of k will the pair of linear equation kx+3y=k-3 ; 12x+ky=k

Answer 1

Answer:

Step-by-step explanation:

value of k for which the given pair of linear equations has no solution is k = – 6.

                                        OR

The given pair of linear equation can be written as

kx+3y−k+3=0 and  12x+ky−k=0

Here, a  

1

​

=k,b  

1

​

=3,c  

1

​

=−k+3 and a  

2

​

=12,b  

2

​

=k,c  

2

​

=−k

Now, the given pair of linear equation has no solution if

a  

2

​

 

a  

1

​

 

​

=  

b  

2

​

 

b  

1

​

 

​

 



=  

c  

2

​

 

c  

1

​

 

​

⇒  

12

k

​

=  

k

3

​

 



=  

−k

−k+3

​

 

12

k

​

=  

k

3

​

 and  

k

3

​

 



=  

k

k−3

​

 

k  

2

=36 and 3



=k−3

k=±6 and k



=6

k=−6

Hence, the given pair of linear equation has no solution if k=−6.