Fora cel, the terminal potential ofference is 22V when circuit is open and reduces
to 18 V, when cel is connected to a resistance R-50. The internal resistance (0)
of cell is
(1090 ( 9/10
(-) 1190 (W) 5/90
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Answer:
let internal resistance be r
then R equivalent = (50 + r)ohm
V = V1 + V2
22 = 18 + V2
V2 = 4 i.e. the voltage taken by internal resistance
18 = I. 50
I = 9/25 current remains same in series
4 = I. r
4 = 9/25 .r
r = 100/9ohm
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