Forces of 10√2 N and 5√2 N are acting on the body of mass √14 kg at an angle of 60° to each other. Find the acceleration, distance travelled and the velocity of the mass after 10s.
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F=m x v/t but there is change in force so,
F'-F = m x v/t cos 60°
10√2 - 5√2 = √14 x v/10 x 1/2
5√2 = √14 V/20
V = 120/√14
acceleration, a=v/t so, a = 12/√14
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