Question

form the pair of equation in this problem, and find its solution ( of it exist ) by the elimination method :-.

if we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes 1/2 if we only add 1 to the numerator. what is this fraction?

Please ans it ASAP

Answer 1

hey friend,
according to Ur question, the numerator shall be 0 and the denominator 2
thus the fraction is (0/2) which =0
hope it helped.
: )

Answer 2

Hi

Let the fraction = x / y ------(1)

According to the problem

( x + 1 )/ ( y - 1 ) = 1

x + 1 = y - 1

x - y = -2 ---------(2)

( x + 1 )/ y = 1/2

2( x + 1) = y

2x + 2 = y

2x - y = - 2 ----------(3)

Subtract. (2) from (3) we get

x = 0

Put x= 0 in (2) we get

y = 2

Therefore x = 0 and y = 2

Put these values in ( 1 )

Required fraction = x / y = 0/ 2 = 0

Hope this will helps you.


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