Question

Form the quadratic equation:find two constructive odd positive integers sum of whose squares are 290

Answer 1

Answer:

x²+2x-143=0

Step-by-step explanation:

Let the consecutive odd positive integers be x and x+2

Then,

x² + (x+2)² = 290

x²+x²+4x+4=290

2x²+4x =286

2x²+4x-286=0

(÷2)

x²+2x-143=0