Math, asked by raj7sha9kkunturve, 1 year ago

formula for a-b-c whole cube??? and a+b+c+ whole cube???

Answers

Answered by mysticd
21
Hi ,

i ) ( a - b - c )^3

= ( a - b - c ) ( a - b - c)^2

= (a-b-c)(a^2+b^2+c^2-2ab+2bc-2ac)

= a^3+ab^2+ac^2-2a^2b-2abc-2a^2c

-a^2b-b^3-bc^2+3ab^2-2b^2c+2abc

-a^2c-b^2c-c^3+2abc-2bc^2+2ac^2

= a^3-b^3-c^3+3ab^2+3ac^2-3a^2b

-3a^2c-3bc^2-3b^2c +3abc

ii) (a+b+c)^3

=( a+b+c)(a+b+c)^2

= a^3+b^3+c^3+3ab^2+3ba^2+3bc^2

+ 3b^2c+3ca^2+3ca^2+ 6abc

I hope this helps you.

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Answered by Suhanithisside
0

Answer:

i ) ( a - b - c )^3

= ( a - b - c ) ( a - b - c)^2

= (a-b-c)(a^2+b^2+c^2-2ab+2bc-2ac)

= a^3+ab^2+ac^2-2a^2b-2abc-2a^2c

-a^2b-b^3-bc^2+3ab^2-2b^2c+2abc

-a^2c-b^2c-c^3+2abc-2bc^2+2ac^2

= a^3-b^3-c^3+3ab^2+3ac^2-3a^2b

-3a^2c-3bc^2-3b^2c +3abc

ii) (a+b+c)^3

=( a+b+c)(a+b+c)^2

= a^3+b^3+c^3+3ab^2+3ba^2+3bc^2

+ 3b^2c+3ca^2+3ca^2+ 6abc

I hope this helps you.:D

Step-by-step explanation:

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