formula for a-b-c whole cube??? and a+b+c+ whole cube???
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Answered by
21
Hi ,
i ) ( a - b - c )^3
= ( a - b - c ) ( a - b - c)^2
= (a-b-c)(a^2+b^2+c^2-2ab+2bc-2ac)
= a^3+ab^2+ac^2-2a^2b-2abc-2a^2c
-a^2b-b^3-bc^2+3ab^2-2b^2c+2abc
-a^2c-b^2c-c^3+2abc-2bc^2+2ac^2
= a^3-b^3-c^3+3ab^2+3ac^2-3a^2b
-3a^2c-3bc^2-3b^2c +3abc
ii) (a+b+c)^3
=( a+b+c)(a+b+c)^2
= a^3+b^3+c^3+3ab^2+3ba^2+3bc^2
+ 3b^2c+3ca^2+3ca^2+ 6abc
I hope this helps you.
***
i ) ( a - b - c )^3
= ( a - b - c ) ( a - b - c)^2
= (a-b-c)(a^2+b^2+c^2-2ab+2bc-2ac)
= a^3+ab^2+ac^2-2a^2b-2abc-2a^2c
-a^2b-b^3-bc^2+3ab^2-2b^2c+2abc
-a^2c-b^2c-c^3+2abc-2bc^2+2ac^2
= a^3-b^3-c^3+3ab^2+3ac^2-3a^2b
-3a^2c-3bc^2-3b^2c +3abc
ii) (a+b+c)^3
=( a+b+c)(a+b+c)^2
= a^3+b^3+c^3+3ab^2+3ba^2+3bc^2
+ 3b^2c+3ca^2+3ca^2+ 6abc
I hope this helps you.
***
Answered by
0
Answer:
i ) ( a - b - c )^3
= ( a - b - c ) ( a - b - c)^2
= (a-b-c)(a^2+b^2+c^2-2ab+2bc-2ac)
= a^3+ab^2+ac^2-2a^2b-2abc-2a^2c
-a^2b-b^3-bc^2+3ab^2-2b^2c+2abc
-a^2c-b^2c-c^3+2abc-2bc^2+2ac^2
= a^3-b^3-c^3+3ab^2+3ac^2-3a^2b
-3a^2c-3bc^2-3b^2c +3abc
ii) (a+b+c)^3
=( a+b+c)(a+b+c)^2
= a^3+b^3+c^3+3ab^2+3ba^2+3bc^2
+ 3b^2c+3ca^2+3ca^2+ 6abc
I hope this helps you.:D
Step-by-step explanation:
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