Formula for arithmetic progression to find the no of terms
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Formula for arithmetic progression to find the no of terms=a+(n-1)d where a is first term of AP and d is common difference.
EXAMPLE
1,2,3,4..........10
Let last term be 10
a=1 nd d=1
l=a+(n-1)d
10=1+(n-1)1
10-1=n-1
9=n-1
9+1=n
10=n
hence no of terms =10
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