formula for internal division
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if a line is divided internally in m:n by a point then the coordinate of point is given by-
x=mx2-nx1/m+n ,y=my2-ny1/m+n
its coordinate can be found by this formula
x=mx2-nx1/m+n ,y=my2-ny1/m+n
its coordinate can be found by this formula
Answered by
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HELLO DEAR,
If there are two points P(x1,y1) and Q(x2,y2),, and the line segment PQis divided internally by point R(x,y) in the ratio m:n,then, the coordinates of R(x,y) are as under:
I HOPE ITS HELP YOU DEAR,
THANKS
If there are two points P(x1,y1) and Q(x2,y2),, and the line segment PQis divided internally by point R(x,y) in the ratio m:n,then, the coordinates of R(x,y) are as under:
I HOPE ITS HELP YOU DEAR,
THANKS
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