Question

Four cells each of emf 2v internal resistance 1 ohm are connected in parallel with an external resistant of 6 ohm the current in the external resistance is

Answer 1

Answer:

Hope this helps you.....

Explanation:

I=E÷R+r/n

=2÷6+1/4

=2×4/25

=8/25

=0.32

Answer 2

GIVEN:  No of cells = 4

              emf of each cell = 2v

               internal resistance = 1Ω

               external resistance = 6Ω

               type of combination =  parallel

TO FIND: current (I)

SOLUTION:

The formulae to calculate the current in the external circuit are as follows-

I = $\frac{E}{R+\frac{r}{n} }$

E = This denotes the electromotive force

R =  This denotes the resistance of the circuit

r = This denotes the internal resistance of the cell

n = This denotes the number of the cells.

I = $\frac{2}{6 + \frac{1}{4} }$

Taking 4 as LCM in the denominator.

6 + $\frac{1}{4}$ = $\frac{24 + 1 }{4}$ = $\frac{25}{4}$

Substituting $\frac{25}{4}$ in the denominator of the current equation.

I = $\frac{2}{\frac{25}{4} }$

I = $\frac{2}{1}$ × $\frac{25}{4}$

I = $\frac{8}{25}$

I = 0.32Ω

The current in the external resistance is 0.32Ω.

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