Four consecutive odd integers sum to 136. What is the greatest of these integers?
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let on integer be x
then other integers are x+2 ,x+4 ,x+6
sum of integers = 136
x+ x+2 + x+4 + x+6= 136
4x + 12 = 136
4x =136-12
4x = 112
x = 112/4
x = 28
integer are 28
28+2 = 30
28+4= 32
28+6 =34
answer is 34
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