Question

Four numbers are in AP .the sum of the first three term is 21 and sum.of the last three term.is 30.find the numbers

Answer 1

Answer:HELLO DEAR,

Let the 4 numbers are a , a + d , a + 2d , a + 3d.

Sum of first 3 numbers = 21

a + a + d + a + 2d = 21

⇒ 3a + 3d = 21

⇒a + d = 7 ---------------( 1 )

And the sum of last three no. = 30

⇒ a + d + a + 2d + a + 3d = 30

⇒3a + 6d = 30

⇒a + 2d = 10--------------( 2 )

From----------( 1 ) & ------(2)

a + d = 7

a + 2d = 10

–––––––———

-d = -3

d = 3 [ put in -------( 1 ) ]

we get,

a + 3 = 7

a = 7 - 3

a = 4 , d = 3

now, the numbers are, a = 4 , (a + d) = 7 ,(a + 2d) = 10 , (a + 3d) = 13

AP : 4 , 7 , 10 , 13

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Answer:

this is the answer of your question ✌️.