Physics, asked by athira2410, 1 year ago

four point charges Q,q,Q,q are placed at the corners of a square of side a find the resultant electric force on a charge Q

Answers

Answered by Light1729
29
Resultant force on Q is
\frac{kQ^2}{2a^2}+\sqrt{2}\frac{kQq}{a^2}

pranavkulkarni9880: explain brief
Ananthukerala: Can you explain please how its √2, shouldnt it be 2?
Light1729: because two of the forces are perpendicular to each other, so we have to find the resultant and hence we get √2
sumangill135: plZ tell me "potential energy of its systam"
sumangill135: plz
Answered by phillipinestest
13

Resultant electric force on charge Q is  \bold{F_{n e t}=\left[\frac{1}{4 \pi \varepsilon_{0}} \frac{Q}{a^{2}}\left(\frac{Q}{2}+q \sqrt{2}\right)\right] N}

Solution:

The net force resulting on charge Q at the center by the four point charges at corner of the square of length a are calculated as follows,

Given: Point charges as “Q, q Q and q”.

Square side = a

Force on charge Q imposed by charge q will be, F=\frac{1}{4 \pi \varepsilon_{0}} \frac{q Q}{a^{2}}

Force on charge Q imposed by charge Q will be, F=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q^{2}}{\sqrt{2} a^{2}}

Force on charge Q imposed by charge q and q will be, F=\frac{1}{4 \pi \varepsilon_{0}} \frac{q Q}{a^{2}} \sqrt{2}

Therefore, Net resultant of force acting on charge Q by all the four point charges be –

 \bold{F_{n e t}=\left[\frac{1}{4 \pi \varepsilon_{0}} \frac{Q}{a^{2}}\left(\frac{Q}{2}+q \sqrt{2}\right)\right] N}

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