Question

fourteen identical resistors each of resistance r are connected as shown calculate equivalent resistance between a and b​

Answer 1

Answer:

Where is the figure bro

Answer 2

Thus the resistance between a and b is 1.2 r.

Explanation:

• If the battery of emf V is connected across A and E.
• Current is BD and FE are identical to each other (I2,say).
• Currents i BF and HD are identical to each other (I3 say) no
• currents flows through BH and DF hence currents through

Different resistors will be as shown in figure applying Kirchhoff's voltage law at junction B, we get.

e ≥ tI3r - (2) / (3)r I2 = 0

or 3I3 = 2I2 (ii)

Now apply ∈ g Kirchhoff's vo <a≥ law on mesh AHFEJKA ,we ≥ tI1r +I2((2) / (3r) + I1r- V = 0

I1 = I2 + I3

I = 2I

1 =5I3

Therefore, a≤ nht resistance is (V) / (5I3) = (1)/(5) x 6 r  = 1.2 r

Also learn more

For the circuit shown in the diagram below:

what is the value of:  (i) current through 6 Ohm resistor? (ii) potential difference across 12 ohm resistor?

given:-V=4V, R1= 6 ohm, R2= 3 ohm, R3= 12ohm, R4= 3 ohm

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