fourteen identical resistors each of resistance r are connected as shown calculate equivalent resistance between a and b
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Answer:
Where is the figure bro
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Thus the resistance between a and b is 1.2 r.
Explanation:
- If the battery of emf V is connected across A and E.
- Current is BD and FE are identical to each other (I2,say).
- Currents i BF and HD are identical to each other (I3 say) no
- currents flows through BH and DF hence currents through
Different resistors will be as shown in figure applying Kirchhoff's voltage law at junction B, we get.
e ≥ tI3r - (2) / (3)r I2 = 0
or 3I3 = 2I2 (ii)
Now apply ∈ g Kirchhoff's vo <a≥ law on mesh AHFEJKA ,we ≥ tI1r +I2((2) / (3r) + I1r- V = 0
I1 = I2 + I3
I = 2I
1 =5I3
Therefore, a≤ nht resistance is (V) / (5I3) = (1)/(5) x 6 r = 1.2 r
Also learn more
For the circuit shown in the diagram below:
what is the value of: (i) current through 6 Ohm resistor? (ii) potential difference across 12 ohm resistor?
given:-V=4V, R1= 6 ohm, R2= 3 ohm, R3= 12ohm, R4= 3 ohm
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