In a trapezium ABCD,AB is perpendicular to CD,DA is perpendicular to AB,DC=7cm,CB=10 cm and AB =13 cm. Find the area of quadrilateral
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Answer:
Answer:
80 cm²
Step-by-step explanation:
GIVEN:-
AB║DC
DA⊥AB
DC =7 cm
CB=10 cm
AB=13 cm
TO FIND:-
area of the quadrilateral ABCD
SOLUTION:-
Draw CM⊥AB
∴AM=DC=7 cm
MB=AB-AM
=13-7
=6 cm
∴In rt. ∠d ΔCMB,
CM²=10²-6²
=(10+6)(10-6)
=16*4
CM² =64
CM=√64=8 cm
∴Ar(ABCD)=Area of Trapezium
=1/2×height×sum of parallel sides
=1/2×8×(13+7)
=4*20
=80 cm²
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