Question

Frame the equations and solve:
b) Raju is four years younger than Biju. Sum of their ages is 28.Find their ages

Answer 1

Let Biju's age be x
Then Raju's age will become x-4
Sum of their ages = 28
Therefore
x + x-4 = 28
2x - 4 = 28
2x = 28+4
2x = 32
x = 32/2
x = 16
means Biju is 16 years old and Raju is 16-4 = 12 years old

Answer 2

Let biju age will = x years. Therefore Raju age =(x-4) years. A/Q : x+(x-4) = 28 => 2x -4 =28. =>. 2x = 28+4 =>. 2x = 32. so; x = 32/2. = 16. biju age = 16 , Raju age = 16-4 = 12. Hope it will help you thanks