Freezing point of a 4 percent aquaeous solution is equal to a
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- since both the solution are aqueous solution , the actual freezing point of solution.( if number solute was added) would have been 0°c. 2.given that both the solution have same freezing point, one can say that the depression in the freezing point would also be the same for both the solution, this , one can write. ∆Tf(A) =∆Tf(B) . 3.Thus,. Kf * molarity (A) = Kf * molarity (B). putting the above values, one can easily get the answer. hope it's help to u marks me brainlist plz
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