from a bag of 52 playing cards , jacks, Queen and Kings of red colour are removed . from the remaining a card is drawn at random . find the probability that drawn card is : a black king , a card of red colour and a card of black colour
Answers
Answer:
(i) 1/23
(ii) 10/23
(iii) 13/23
Step-by-step explanation:
Total no. of outcomes = 52 - 6 = 46 (because there are 6 face cards of red color)
No. of black kings = 2
P(Black king) = 2/46 = 1/23
Now, No of red cards = 26 - 6 = 20 (because there are 26 red cards in total and 6 red cards were removed)
P(red card) = 20/46 = 10/23
Now, No. of black cards = 26 (because no black card was removed)
P(Black Card) = 26/46 = 13/23
Hope it helps.
Answer:
Total number of outcomes = 52
Cards removed = 2+2+2+2 = 8[2 jack, 2 queen, 2 king and 2 aces of red colour]
Remaining number of cards = 52 – 8=44
Total number of outcomes = 44
(i) Favourable outcomes = 2 [There are 2 black queen]
Required probability =
(ii) Favourable outcomes = number of red cards left = 26 – 8=18
Probability for a red card =
(iii) Favourable outcomes = Number of black jacks = 2
Required probability =
(iv) Number of picture cards left =2+2+2 = 6 [jack, queen, King are picture cards]
Required probability =
(v) Honorable cards [ace, jack, queen and king]
No. of honorable cards left = 2+2+2+2=8
Required probability =