from a circular sheet of radius 4cm,a circle of rafius 3vm is removed.find the area of the remaining sheet.takeπ=3.14
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Answered by
4
hiii!!!
here's ur answer...
given the radius of the circular sheet is 4cm.
area of the circular sheet = πr²
= 3.14×4×4
= 3.14×16
= 50.24cm²
given the radius of the circle which is removed from the circular sheet is 3cm.
area = πr²
= 3.14×3×3
= 3.14×9
= 28.26cm²
hence area of the remaining sheet = 50.24 - 28.26
= 21.98cm²
hope this helps..!
here's ur answer...
given the radius of the circular sheet is 4cm.
area of the circular sheet = πr²
= 3.14×4×4
= 3.14×16
= 50.24cm²
given the radius of the circle which is removed from the circular sheet is 3cm.
area = πr²
= 3.14×3×3
= 3.14×9
= 28.26cm²
hence area of the remaining sheet = 50.24 - 28.26
= 21.98cm²
hope this helps..!
Answered by
2
Area of circular sheet = πr^2
= 3.14*4*4
= 50.24cm^2
Area of circle removed = 3.14*3*3
= 28.26cm^2
Area of remaining sheet = 50.24 - 28.26cm^2
= 21.98cm^2
= 3.14*4*4
= 50.24cm^2
Area of circle removed = 3.14*3*3
= 28.26cm^2
Area of remaining sheet = 50.24 - 28.26cm^2
= 21.98cm^2
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