Math, asked by hansananya2007, 9 months ago

From a log 11 m long, two pieces of length 23/5 m and 33/10 m are cut off. What is the
length of the remaining log?(with calculation )














Answers

Answered by arka00780
4

Answer:

3.1 m

Step-by-step explanation:

Total length = 11 m

Length of the first piece = 23/5 m = 4.6 m

Length of the second piece = 33/10 m = 3.3 m

Therefore,

Remaining length = (11 - 4.6 - 3.3) m

= 3.1 m

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