from a solid cylinder of height 15cm, and diameter 16cm a conical cavity of the same height and same diameter are hollowed out. find the surface area of the remaining solid to the nearest cm2
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Even if the volume of a solid is hollowed out, its TSA remains the same,so to find the TSA of the cone,use the formula base area+CSA =πrl+πr2=πr(l+r).
Here, radius(r)=16/2=8cm,π=3.14
To find the slant height of the cone,we use the formula l2=r2+h2
l2=82+152
l2=64+225
l=√289=17
Now,TSA of cone[πr(l+r)]=3.14×8(17+8)
=3.14×8×25
=628 cm2
Therefore, total surface area of the remaining solid is 628 cm2.
Here, radius(r)=16/2=8cm,π=3.14
To find the slant height of the cone,we use the formula l2=r2+h2
l2=82+152
l2=64+225
l=√289=17
Now,TSA of cone[πr(l+r)]=3.14×8(17+8)
=3.14×8×25
=628 cm2
Therefore, total surface area of the remaining solid is 628 cm2.
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