Question

from an equation whose roots are only 2 and -3​

Answer 1

Answer:

alpha + bheta = -3 = -b/a

alpha × bheta = 2 = c/a

by comparing a = 1

b = 3

c = 2

x^2 + 3x + 2

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Answer 2

Answer:

$\alpha = 2 \: and \: \beta = - 3 \\ then \: \alpha + \beta = \frac{ - b}{a} \\ = 2 + ( - 3) \\ = - 1 \\ \alpha \beta = \frac{c}{a} \\ = 2. - 3 \\ = - 6 \\ so \: \: we \: got \: a = 1.b = 1.c = - 6$

$by \: these \: a {x}^{2} + bx + c = 0 \\ = {x }^{2} + x - 6 = 0$

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