Question

From an external point P, two tangents PQ and PR are drawn to a circle of radius 4 cm with Centre O. If Angle QPR=90°,then LRNGHT of PQ.

Answer 1

Answer:

4Cm As PQOR IS A SQUARE.

Step-by-step explanation:

Tangents make 90° at the point of intersection.

Thus PQO and PRO are 90°.

QPR is given 90°.

Therefore,

QOR = 360- (PQR+PRO+QPR)=

=360 - (90+90+90)

=90.

THUS PQOR is a square. with each side equal to 4cm ( radius of circle-QO ).

Answer 2

Answer:

Angle QPR = 90, the radius touvhe the tangents to form 90º angle... Add... All angles = 90º. Radius are qual in length. Tangents from external point are equal in length. So, it is a square. Hence, PQ = 4cm.

Step-by-step explanation: