Question

from figure,find the lenght of AB and BC.

Answer 1

please refer to the attachment for solution

Answer 2

As we have AC so we can easily find AB andBC...
to find AB we will take
AC as the hypotenuse
AB as perpendicular
BC as base
so now,
$\frac{(p)ab}{(h)ac} = sin 30 \\ \frac{ab}{12} = \frac{1}{2} \\ so \: ab = 6cm$
so to find BC,
we will take
AC as the hypotenuse
BC as perpendicular
ab as base...
BC/AC =sin 60
BC /12=√3/2
BC =6√3
BC =10.392