Question

From the difference of p2 + 4pq – 3q2 and -5pq + 2q2
, add –p
2 – 7pq + 3q2
.

Answer 1

Answer:

$-2pq-2q^{2}$

Step-by-step explanation:

$Difference: \\(p^2+4pq-3q^2) - (-5pq +2q^2)\\p^2+4pq-3q^2+5pq-2q^2\\Regrouping:\\p^2+4pq+5pq-3q^2-2q^2\\=p^2+9pq-5q^2\\\\\\Sum: \\(-p^2-7pq+3q^2) + (p^2+9pq-5q^2)\\-p^2-7pq+3q^2+p^2+9pq-5q^2\\Regrouping:\\-p^2+p^2-7pq+9pq+3q^2-5q^2\\\\=-2pq-2q^2$

Hope it helps.

Thank you :)