From the figure given below Calculate the length of CD
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given,
BC = 15 m
angle ADE = 22°
angle ACB =47 °
tan22° = AE/DE
tan22° DE =AE ---------(1)
again,
tan47° = AB/BC
tan47° =(AE + BE)/BC
we know,
BCDE is rectangle ,
so,
CD = BE
BC =DE
now ,
tan47° =(tan22°BC + CD)/BC
tan47°. BC -tan22°BC =CD
CD =15(tan47° - tan22° ) m
=15(1.0723 -0.404 )
=15(0.6683)
=10.03 m
BC = 15 m
angle ADE = 22°
angle ACB =47 °
tan22° = AE/DE
tan22° DE =AE ---------(1)
again,
tan47° = AB/BC
tan47° =(AE + BE)/BC
we know,
BCDE is rectangle ,
so,
CD = BE
BC =DE
now ,
tan47° =(tan22°BC + CD)/BC
tan47°. BC -tan22°BC =CD
CD =15(tan47° - tan22° ) m
=15(1.0723 -0.404 )
=15(0.6683)
=10.03 m
Rutvi27:
answer
Answered by
3
Answer:
answer is 10.03 metre
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