from the given figure, find angle BPC ? ( PLS ANS THIS IN DETAIL AND URGENTLY )
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Is that all that's given?
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sum of the opposite angle of cyclic quadrilateral = 180 degree
ie <A + <C = 180
<B + <D = 180
therefore, <C = 180 - 75 = 105
& <B = 180 - 77 = 103
the sum of the triangle BPC = 180
<B + <C + <P = 180
103/2 + 105/2 + <P = 180 ( because it cut at bisector)
51.5 + 52.5 + <P = 180
<P = 180 - 104
<P = 76
ie angle BPC = 76
ie <A + <C = 180
<B + <D = 180
therefore, <C = 180 - 75 = 105
& <B = 180 - 77 = 103
the sum of the triangle BPC = 180
<B + <C + <P = 180
103/2 + 105/2 + <P = 180 ( because it cut at bisector)
51.5 + 52.5 + <P = 180
<P = 180 - 104
<P = 76
ie angle BPC = 76
It doesn't say anything about a bisector, you're just assuming so.
yes if you assume it to be bisector
I'm not sure that's the wisest thing to do but whatever
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