Physics, asked by anas3152002, 11 days ago

From the Kepler's law of areas, dA/dt=______
A.L/2F
B.2F/L
C.2m/L
D.Lz/2m​

Answers

Answered by Anonymous
0
Now, the angular momentum L of the planet in its orbit is given by. so the rate of sweeping out of area is proportional to the angular momentum, and equal to L/2m. Newton's Laws tell us that the rate of change of angular momentum is equal to the torque of the forces acting on the system
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