Question

from the quadratic equation whose roots are 2/3 and 5/2​

Answer 1

Step-by-step explanation:

Let 'm' and 'n' be the roots ∴m=2,n=3

Sum of the roots =m+n=2+3∴m+n=5

Product of the roots =mn=(2)(3)∴mn=6

Standard form is x^2

−(m+n)x+mn=0∴x^2

x^2 −(5)x+(6)=0

−5x+6=0

Answer 2

Step-by-step explanation:

let a=2/3,b=5/2

=> a+b= 19/6

a×b =5/3

so equation is ...x^2-(a+b)x+a×b=0

=> x^2-19/6x+5/3=0

6x^2-19x+10=0