Question

from the sum of 2p^2 - 3q^2 + 4r^2 and p^2 +2q^2 - 3r^2 , subtract 4p^2 + 2q^2 - 3r^2

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Answer 1

Addition of the polynomials:

(2p² - 3q² + 4r²) + (p² + 2q² - 3r²)

→ 2p² - 3q² + 4r² + p² + 2q² - 3r²

→ (2p² + p²) + (-3q² + 2q²) + (4r² - 3r²)

→ 3p² - q² + r²

Subtraction of the polynomials:

3p² - q² + r² - (4p² + 2q² - 3r²)

→ 3p² - q² + r² - 4p² - 2q² + 3r²

→ (3p² - 4p²) + (-q² - 2q²) + (r² + 3r²)

→ -p² - 3q² + 4r²

Answer 2

Step-by-step explanation:

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