Question

From the sum of 3 + 4x and - 3 + 7x subtract - x ^ 2 + 10x + 3 pls help
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Answer 1

Step-by-step explanation:

We have,

3+4x + (-3+7x)= 3+4x -3-7x

= -3x

Therefore,

(-x^2 +10x +3) -3x = -x^2 + 7x + 3

Answer 2

Answer:

$\huge\mathcal\green{Question:-}$

From the sum of 3 + 4x and - 3 + 7x subtract - x ^ 2 + 10x + 3

$\huge\mathfrak\pink{Solution}$

First we have to find the sum of 2+4x and -3+7x

$\mapsto \: 3 + 4x + ( - 3 + 7x)$

We have to remove brackets

If positive symbol is multiplied by negative symbol always we get negative symbol

$\mapsto \: 3 + 4x - 3 + 7x$

Grouping like terms

$\mapsto \: 3 - 3 + 4x + 7x$

$\mapsto \: 11x$

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Next we have find the difference of these two terms

Before we finding the difference we have to change the negative x into positive x

$- x ^{2} + 10x + 3$

If x is multiplied two times we get positive

$x + 10x + 3$

By finding the difference we get,

$11x - (x + 10x + 3)$

Removing the brackets,

$11x - x -10x -3$

$\mapsto \: 22x + 3$

Answer is -3

Step-by-step explanation:

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