Question

From the top of a building 15 meter high, the angle of elevation of the top of a tower is found to be 60 degree. from the bottom of the same building, the angle of elevation of the top of the tower is found to be 60 degree. find the height of the tower and the distance between the tower and the building.

Answer 1

h of building= 15m
tan thetha=perpendicular/base
tan 60=15/base
(3^1/2)=15/ base
base=15/(3^1/2)
        =15x(3^1/2)/3
        =5x(3^1/2)
base of tower=5x(3^1/2)
tan thetha=perpendicular/base
tan60=h/5x(3^1/2)
(3^1/2)=h/5x(3^1/2)
h=(3^1/2)x5x(3^1/2)
          =5x3
          =15
height of tower=15m
dist. b/w building=base=5x(3^1/2)m