Question

from the top of a tower, the angle of depression to the roof of a house 10m high and 40 m away from the base of tower, was observed and found to be 30 degree. find the height of the tower.

Answer 1

Answer:

Tan 60 =1.732

Tan 30 = .5774

Y = Distance from the tower angle of elevation of 60°

(Y+60) = Distance from the tower angle of elevation Of 30°

X = Tower height

X divided by Y = 1.732

X= 1.732 Y

X /(Y +60) equals .5774

1.732 Y/ (Y+60) = .5774

1.732 Y = .5774 Y + 34.61

1.1546 Y = 34.61

Y = 29.9757

X = 1.732×29.757 = 51.96 m

X = 89.9757 x .5774 = 51.95 m

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Answer 2

Answer:

The height of the tower is the sum of the height of the building (10 m) and the remaining height (x m).

Use the appropriate trigonometric function, along with the distance to the building (40 m) to calculate x.