Question

From the top of the tower, a ball A is dropped and another ball B is thrown horizontally at the same time. Which ball strikes the ground first ?

Answer 1

Answer:

Both the balls strike the ground at the same time.

Explanation:

In both the cases, initially, the vertical velocity is zero.(Case 1 is freefall whereas Case 2 is horizontal projectile motion, where the object starts with zero vertical velocity, i.e., velocity is completely horizontal.)

So by Newton's laws of motion,

s = ut+1/2gt²

In the vertical direction ( i.e., the y axis )

s = same for both (as both the bodies travel the same vertical height)

u (along y axis) = 0

So from here we can understand that since s is equal for both and u = 0, the time in both cases is going to be the same.

Therefore, both the balls reach the ground at the same time.

I hope that helps you.

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