Question

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Answer 1

Answer:

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${\huge{\sf{\blue{\underline {\underline{Question}}}}}}$

Find the area of a triangle, two sides of which are 18cm and 10cm and the perimeter is 42 cm :

Answer :-

Given that,

Two sides of triangle are 18 cm and 10 cm.

Perimeter of triangle is 42 cm

Let, third side of triangle be x .

So,

⟶ Perimeter = 18 + 10 + x

⟶ 42 = 28 + x

⟶ 42 - 28 = x

⟶ x = 14

Third side of triangle is 14 cm.

Now,

s = 42/2

s = 21

Semi-perimeter is 21 cm.

Area of traingle :

⟶ √21 × (21 -18)(21 -14)(21 - 10)

⟶ √21 × 3 × 7 × 11

⟶ √3 × 7 × 3 × 7 × 11

⟶ 3 × 7 √11

⟶ 21 × √11

Put √11 = 3.316

⟶ 21 ×3.316

$\longrightarrow \blue{\boxed{\bold{69.639}}\bigstar}$

★

Area of triangle is 69.636 cm²

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Formulas used:-

• Perimeter of triangle = Sum of all sides

• Heron's formula that is

Area of traingle = √s(s - a)(s - b)(s - c)

where,

s is semi-perimeter of triangle.

a, b and c are sides of triangle.

• Semi-perimeter = Perimeter of triangle/2

Answer 2

Explanation:

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