Question

g(X)=a(x^2+1)-x(a^2+1) find the zeroes​

Answer 1

Answer:

Equation = G(X)=a(x²+1)-x(a²+1)

G(x) = ax² + a -a²x -x

= ax² - x - a²x +a

= x(ax-1) -a(ax -1)

(ax-1)(x-a) = 0

x = 1/a. And. x = a

Thus

Required zeros are 1/a and a.

Hope this will help you.