(genius can solve this question) if sin theta=6/10, find, without using cable, the value of cos theta + tan theta.
Answers
Answered by
0
If sin theta=6/10 =opp/hyp then by pythagoras theorem Cos theta =8/10 ,tan theta=6/8=sin theta/cos theta=3/4
Answered by
0
sin theta = 6/10 = opposite/hypertenuse
sin A = 6/10
in triangle ABC,AB = 10(hypertenuse)
BC = 6(base)
AC = √10²-6²
= √100-36
= √64
= 8
cos theta = 8/10 = adjacent/hypertenuse
tan theta = 6/8 = opposite/adjacent
cos theta + tan theta = 8/10 + 6/8
= 32+30/40(LCM)
= 62/40
= 1.55
HOPE ITS HEPLS............
sin A = 6/10
in triangle ABC,AB = 10(hypertenuse)
BC = 6(base)
AC = √10²-6²
= √100-36
= √64
= 8
cos theta = 8/10 = adjacent/hypertenuse
tan theta = 6/8 = opposite/adjacent
cos theta + tan theta = 8/10 + 6/8
= 32+30/40(LCM)
= 62/40
= 1.55
HOPE ITS HEPLS............
Similar questions