Question

give possible expression for the length and breadth of the rectangle which has area =a^2-6a+8

Answer 1

Hey friend..!! here's your answer
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a^2 - 6a + 8
a^2 -4a - 2a + 8
a ( a - 4) - 2 ( a - 4 )
(a -2 ) (a - 4)
a = 2 or a = 4

So that the length of rectangle is 2 and breadth is 4 .

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#Hope its help you dear#
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Answer 2

HELLO......FRIEND!!

THE ANSWER IS HERE,

$= > \: {a}^{2} - 6a + 8$

$= > \: {a}^{2} - 4a - 2a + 8$

$= > \: a(a - 4) - 2(a - 4)$

$= > \: (a - 4)(a - 2)$

Area = Length × breadth.

So,
Length of the rectangle => a-2.

Breadth of the rectangle => a-4.


:-)Hope it helps u.