Give quantum number for electron with highest energy in sodium atom
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For Na 1s^2 2s^2 2p^6 3s^1, for highest energy, n=3 l=0 m=0 s=1/2, and thus, it is calculated and So that n+l is highest.
In fact, the electron with the highest energy can be measured by taking sodium atom with the highest valence electron in single electron presents in 3s orbital.
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2
Answer:
n = 3, l = 0, m = 0 and s =+1/2or−1/2
Solution :
Electron configuration of Na=1s2,2s2,2p6,3s−1. The electron with highest energy is 3s1 for which n=3,l=0
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