Question

Give simple chemical tests to distinguish between the following pairs of compounds: Benzoic acid and Ethyl benzoate

Answer 1

HEY DEAR ... ✌️

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Here's , Your Answer :-


=) We can distinguish Benzoic acid and Ethyl benzoate by sodium bicarbonate test .

=) By reacting NaHCO3 with acids it will produce effervescence due to evolution of CO2 gas.

- As we all know , Benzoic acid is an acid it will definitely respond to the above test .

But , Ethyl Benzoate is not an acid . So , it will not respond to the above test .


=) Reaction :-


For Benzoic acid ...

=] C6H5COOH + NaHCO3 ➡️ C6H5COONa + CO2 + H2O .


For Ethyl Benzoate ...

=] C6H5COOC2H5 + NaHCO3 ➡️ No reaction or respond .

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HOPE , IT HELPS ... ✌️

Answer 2

HELLO DEAR,

these two compounds can be distinguished by the following tests;

( 1 ). $\bold{NaHCO_3\; test}$ benzoic acid being an acid produces brisk effervescence with $\bold{NaHCO_3}$ solution while ethyl benzoate does not.

$\bold{_{_{_{benzoic\; acid}}} C_6H_5COOH + NaHCO_3 \longrightarrow \; _{_{_{sod.\; benzoate}}} C_6H_5COONA + CO_2 \uparrow \; + \; H_2O}$

$\bold{_{_{_{Ethyl\; benzoate}}} C_6H_5COOC_2H_5 + NaHCO_3{\tiny {soln.}} \longrightarrow No \; effervescence\; due \; to \; evolution \; of \; CO_2 gas }$

( 2 ) ethyl benzoate on boiling with NAOH of solution gives ethyl alcohol and (Sodium acetate) which on subsequent heating with iodide gives yellow PPT of idoform.

$\bold{C_6H_5COOCH_2CH_3 + NAOH + BOIL \longrightarrow C_6H_5COONa + CH_3CH_2OH}$

$\bold{CH_3CH_2OH + 4I_2 + 6NaOH + HEAT \longrightarrow HCOONa + _{_{_{yellow\; ppt.}}}CHI_3 + 5NaI + 5H_2O }$

I HOPE IT'S HELP YOU DEAR,
THANKS