Give the geometric interpretation of 3y+15=0 as an equation in (a) one variable & (b) two variables.
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Given, linear equation is 3y+15=0
3Y= -15
Y= -15/3
Y= -5
i)
If Y = -5 is treated as an equation in one variable, then it has a unique solution y= -5. So it is a point on the number line.
[Number line is on the attachment]
ii)
Given equation Y = -5 can be written as 0.x + y+5= 0, which is a linear equation in two variables x and y.
This is represented by a line .Here all the values of X are permissible because 0.x is always 0. However, y must satisfy the equation y=-5
[Graphs on the attachment]
Thus, the graph AB is a line parallel to X-axis at a distance of -5 units in the negative direction of Y axis.
===============================================================
Hope this will help you...
3Y= -15
Y= -15/3
Y= -5
i)
If Y = -5 is treated as an equation in one variable, then it has a unique solution y= -5. So it is a point on the number line.
[Number line is on the attachment]
ii)
Given equation Y = -5 can be written as 0.x + y+5= 0, which is a linear equation in two variables x and y.
This is represented by a line .Here all the values of X are permissible because 0.x is always 0. However, y must satisfy the equation y=-5
[Graphs on the attachment]
Thus, the graph AB is a line parallel to X-axis at a distance of -5 units in the negative direction of Y axis.
===============================================================
Hope this will help you...
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Step-by-step explanation:
3y+15=0
0x+3y+15=0
3y= -15
y = -15/3
y = - 5
x = 0
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