Give the greatest no which divides 926 and 2313 by leaving remainder 2 and 3points questionFast
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Answered by
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When it divides 926, remainder = 2
so it divides = 926-2 = 924
When it divides 2313, remainder = 3
so it divides = 2313-3 = 2310
HCF of 924 and 2310= 462
So the answer is 462
so it divides = 926-2 = 924
When it divides 2313, remainder = 3
so it divides = 2313-3 = 2310
HCF of 924 and 2310= 462
So the answer is 462
Answered by
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The first no. divided by the greatest no. = 926 - remainder
= 926 - 2
= 924
The second no. divided by the greatest no. = 2313 - remainder
= 2313 - 3
= 2310
Therefore the HCF of 926 and 2310 = 462
So, the greatest no. is 462
= 926 - 2
= 924
The second no. divided by the greatest no. = 2313 - remainder
= 2313 - 3
= 2310
Therefore the HCF of 926 and 2310 = 462
So, the greatest no. is 462
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