Question

give the values of x and y by balancing the following: 1) xKNo3 ---> yKNO2 +o2

Answer 1

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■♤ HERE YOUR ANSWER ♤■
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in( 1)
x=2, y=2
2KNO3 ----> 2KNO2+O2

IN (2)
X=4 Y=2
4HCL +O2 ------> 2H2O+2Cl2
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Answer 2

1) The value of $x$ is 2 and $y$ is 2.

2) The value of $x$ is 4 and $y$ is 2.

Given equations are--

$1)xKNO_3 \rightarrow yKNO_2+O_2$

$2)xHCl+O_2\rightarrow yH_2O+2Cl_2$

Considering the law of conservation of mass that states that mass can neither be created nor be destroyed. So, the total mass of reactants and products will be equal. Atoms must be evenly distributed on both sides of the equation in a balanced chemical equation.

In equation 1)

Reactants are = K, N, O

that is,

K = 1

N = 1

O = 3

Products are = K, N, O

that is,

K = 1

N = 1

O = 2+2

   = 4

So, to balance the equation we need multiply $KNO_3$ with 2 and $KNO_2$ with 2. This will make,

$2KNO_3\rightarrow 2KNO_2+O_2$

Reactants--

K = 2

N = 2

O = 3 $\times$ 2

   = 6

Products--

K = 2

N = 2

O = 2 $\times$ 2 + 2

   = 4 + 2

   = 6

Therefore, the value of $x$ is 2 and $y$ is also 2.

In equation 2)

Reactants are = H, Cl, O

that is,

H = 1

Cl = 1

O = 2

Products are = H, Cl, O

that is,

H = 2

Cl = 4

O = 1

So, to balance the equation we need multiply $HCl$ with 4 and $H_2O$ with 2. This will make,

$4HCl +O_2\rightarrow 2H_2O+2Cl2$

Reactants--

H = 4

Cl = 4

O = 2

Products--

H = 4

Cl = 4

O = 2

Therefore, the value of $x$ is 4 and $y$ is 2.

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