give two solutions of (x^2 +x+1)=0 plz fast exam 2morrow
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Use quadratic equation
alpha=[-b+sqrt(b^2-4ac)]/2a
and beta==[-b-sqrt(b^2-4ac)]/2a
where a=1 b=1 c=1
then get the ans as
x2 + x - 1=(x-alpha)(x-beta)
alpha=[-b+sqrt(b^2-4ac)]/2a
and beta==[-b-sqrt(b^2-4ac)]/2a
where a=1 b=1 c=1
then get the ans as
x2 + x - 1=(x-alpha)(x-beta)
vishakha:
thanks last question
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