Question

GIVEN 15 COT A =8, find sin A and sec A

Answer 1

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Answer 2

Answer:

$15 cot A = 8$

$cot A = \frac{8}{15} = \frac{b}{p}$

$h^{2} = b^{2} + p^{2}$

$h^{2} =(8)^{2} +(15)^{2}$

$h^{2} = 64 + 225$

$h^{2} = 289$

$h = \sqrt{289}$

h = 17

$sin A = \frac{p}{h} = \frac{15}{17}$

$sec A = \frac{h}{b} = \frac{17}{8}$