Math, asked by ironman5582, 9 months ago

Given √(2)= 1.4142,√6= 2.4495
find 1/√(3)−√(2)−1​

Answers

Answered by reva4math
0

Answer:

Step-by-step explanation:

Answer:

\frac{1}{\sqrt{3}-\sqrt{2}-1}=-1.464

Step-by-step explanation:

Given : \sqrt{2}=1.414 and \sqrt{6}=2.449

To find : The value of \frac{1}{\sqrt{3}-\sqrt{2}-1}

Solution : First we find the value of \sqrt{3}

\sqrt{6}=2.449

\sqrt{2}\times\sqrt{3}=2.449

1.414\times\sqrt{3}=2.449

\sqrt{3}=\frac{2.449}{1.414}

\sqrt{3}=1.731

Now, put all the values in the expression

\frac{1}{\sqrt{3}-\sqrt{2}-1}

=\frac{1}{1.731-1.414-1}

=\frac{1}{-0.683}

=-1.4641

Up to 3 decimal place = -1.464

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