Given:AB =3y-1, BC =7y, AC=29. Prove: AB=8
Answers
Answered by
1
here's the solution^_^
AB+BC=AC
3y-1+7y=29
3y+7y=29+1
10y=30
y=3......(dividing by 10)
substituting the value of 'y'
AB=3y-1
=3(3)-1
=9-1
=8
therefore AB=8 .....proved
AB+BC=AC
3y-1+7y=29
3y+7y=29+1
10y=30
y=3......(dividing by 10)
substituting the value of 'y'
AB=3y-1
=3(3)-1
=9-1
=8
therefore AB=8 .....proved
Answered by
0
Answer:
AB + BC = AC
3y - 1 + 7y = 29
10y - 1 = 29
10y = 29 + 1 = 30
y = 30/10 = 3
AB = 3(3) - 1 = 9 - 1 = 8
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