Math, asked by MARK0007, 8 months ago

Given an AP such that An= n(5n-3) for every n. Find the 10th term of this progression.

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Answered by k047

given, n term is 5n-3

assume n = 1

therefore, a = 2

first term = 2

for second term assume n = 2

n = 5(2)-3

n = 7

d= 7-a =5

therefore, d = 5

sum of 10 term = 10/2 [2(2)+(10-1)5]

= 5[4+45]

= 5[49]

= 245

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Answered by alaukikasingh17

Answer:

Tenth term of the progress is 470.

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