Question

Given below are the lengths and breaths of some rectangles in cm. Which rectangle has its diagonal bigger than the length by 1 cm ?
1 ) 15 , 9
2 ) 16 , 15
3 ) 12 , 13
4 ) 24 , 7

Answer 1

Answer:

Your required option is (4) i.e 24,7

Step-by-step explanation:

Given that,

Length and breadth of the some rectangle.

1. Length  = 15 cm and Breath = 9 cm

$Diagonal=\sqrt{(length^{2}+breadth^{2})}\\=\sqrt{(15^{2}+9^{2})}\\ =\sqrt{225+81}\\ =\sqrt{306}\\ =17.49$

2.  Length  = 16 cm and Breath = 15 cm

$Diagonal=\sqrt{(length^{2}+breadth^{2})}\\=\sqrt{(16^{2}+15^{2})}\\ =\sqrt{256+225}\\ =\sqrt{481}\\ =21.93$

3. Length  = 12 cm and Breath = 13 cm

$Diagonal=\sqrt{(length^{2}+breadth^{2})}\\=\sqrt{(12^{2}+13^{2})}\\ =\sqrt{144+169}\\ =\sqrt{313}\\ =17.69$

4.Length  = 24 cm and Breath = 7 cm

$Diagonal=\sqrt{(length^{2}+breadth^{2})}\\=\sqrt{(24^{2}+7^{2})}\\ =\sqrt{576+49}\\ =\sqrt{625}\\ =25$

Which is greater than the length by 1 cm.

∴Option 4 is correct.

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Answer 2

Answer:

Its 4 option the answer

Step-by-step explanation:

We can also get the answer by recognizing the Pythagorean triplet

N 24 ²+ 7 ² is equal to 25 ²

so here is answer

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